Calculate the number of atom of each type in 53 gm of Na2co3
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Answer:
=9.033×1022 O atoms.
Explanation:
Calculate the number of atoms of each type in 5.3 g of Na_(2)CO_(3). ∴0.05 mol of Na2CO3 contains =0.05×2×6.022×1023 sodium atoms =6.022×1022 Na atoms. ∴0.05 mol of Na2CO3 contains =0.05×3×6.022×1023 oxygen atoms
=9.033×1022 O atoms.
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