Calculate the number of atoms and molecules present in 44.8 Litres of Nitrogen at NTP. What will be the mass of 22.4 L of Nitrogen at NTP?
Answers
We have to calculate the number of atoms and molecules present in 44.8 L of nitrogen at NTP. and also mass of 22.4L of nitrogen at NTP.
solution : given volume of nitrogen = 44.8L
no of moles of nitrogen = given volume/22.4 L [ volume of 1 mol of an ideal gas at NTP is 22.4 L ]
= 44.8 L/22.4 L
= 2
now no of nitrogen molecules in 2 moles = 2 × Avogadro's number
= 2 × 6.023 × 10²³
= 12.046 × 10²³
= 1.2046 × 10²⁴
we know, chemical formula of Nitrogen gas is N2
so, one molecule of nitrogen gas contains two atoms.
so, no of Nitrogen atoms = 2 × no of molecules
= 2 × 1.2046 × 10²³
= 2.4092 × 10²³
now we have to find the mass of nitrogen of 22.4 L at NTP.
we know, 1 mole of an ideal gas at NTP = 22.4 L
so, no of moles of Nitrogen = 1 mol
now, mass of nitrogen = molecular weight × no of moles
= 28g/mol × 1 mol
= 28g
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