Calculate the number of atoms in 0.2 gram of He
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Atomic mass of He (Helium) = 4 u
=> Molar mass of He = 4g
Given mass = 0.2 g
=> Mole = given mass (in g)/molar mass
=> Mole = 0.2/4
=> Mole = 1/20
=> Mole = 0.05 mol
Now, no. of atoms = mol × Avogadro Number
Avogadro Number = 6.022 × 10²³
=> No.of atoms = 0.05 × 6.022 × 1023
=> 0.3011 × 10²³
=> 3.011 × 10²²
Hope it helps dear friend ☺️✌️
=> Molar mass of He = 4g
Given mass = 0.2 g
=> Mole = given mass (in g)/molar mass
=> Mole = 0.2/4
=> Mole = 1/20
=> Mole = 0.05 mol
Now, no. of atoms = mol × Avogadro Number
Avogadro Number = 6.022 × 10²³
=> No.of atoms = 0.05 × 6.022 × 1023
=> 0.3011 × 10²³
=> 3.011 × 10²²
Hope it helps dear friend ☺️✌️
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