Question

calculate the number of atoms in 10 grams of Gold Ring

Answer 1

Answer:

ATOMIC WEIGHT OF A GOLD = 196.97

THE AVERAGE NUMBER IN ONE MOLE ARE 6.022*10TO THE POWER OF 23

THAT MEANS 6.022*10 TO THE POWER OF 23 ATOM's WEIGH 196.97g

NOW,

1.0g/196.97g = 0.0051 mole

SO THE NUMBER OF ATOMS IN ONE GRAM OF GOLD ARE

0.0051*6.022*10 to the power of 23 =3.057318373*10to the power of 21

Answer 2

Answer:

am weight of gold is 196