calculate the number of atoms in 11.2ml SO2 at 2atm and 273 Ak temp.
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no.of atom= mole of SO2×3×6.02×10^23 here 3 is atomicity of SO2 because in this compound 3 atom present and for mole ofSO2 ,,p×v=n×R×T ,, 2×11.4=n×0.082×273 then mole is 1 after solving this . no. of atom = 1×3×6.02×10^23 then ans is 18.06×10^23 atom
Answered by
0
Answer:
no.of atom= mole of SO2×3×6.02×10^23 here 3 is atomicity of SO2 because in this compound 3 atom present and for mole ofSO2 ,,p×v=n×R×T ,, 2×11.4=n×0.082×273 then mole is 1 after solving this . no. of atom = 1×3×6.02×10^23 then ans is 18.06×10^23 atom.
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