Question

calculate the number of atoms in 18.0 gram of glucose C6 h12 o6​

Answer 1

Here is the solution......

molecular weight of glucose =180g

therefore,

• 180 g glucose contains 6 * 10^23 atoms

0.18g glucose contains.......

= 6*10^23 * 0.18/180 atoms

Answer 2

Answer:

according to formula

no of atoms=mass/molar mass *avogadro number

Explanation:

so

18/180 *6.023*10*23

answer is 0.6023*10*23