Calculate the number of atoms in 2.1g of nitrogen;;calculations please
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Answered by
6
Answer:
2.1×6.02×1023÷ 14
9.03×1022 atom of nitrogen
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3
Explanation:
Given mass= 2.1g
Molar mass of nitrogen = 14*2=28
Number of moles =given mass/molar mass
=2.1/28
=0.075 moles
Number of particles =number of moles *Avogadro's no.
=0.075*6.022*10^23. [consider 6.022 as “6” for easy calculation]
=0.46*10^23 atoms are present in 2.1g of nitrogen
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