Question

calculate the number of atoms in 32 u of helium​

Answer 1

Answer:(i) 1 mol of Ar = 6.022×1023atoms

∴ 52 mol of Ar = 52×6.022×1023atoms = 3.131×1025atoms

(ii) 1 atom of He = 4 u of He

4 u of He = 1 Atom of He

∴ 52 u of He = 1/4 × 52 = 13 atoms

(iii) 1 mol of He = 4 g = 6.022×1023atoms

∴ 52 g of He = (6.022×1023/4) × 52 atoms = 7.8286×1024atoms

Answer 2

Answer:

$\boxed{[tex]\colour{green}{48.176*10^23}$}[/tex]

Explanation:

$proper \: quesion$

calculate number of atoms in 32g ot helium

$\boxed{[tex]\colour{green}{Answer$}[/tex]

$\underline{formula}$

$number \: of \: atoms = \frac{give \: mass}{molar \: mass} \times avogadro \: number$

given mass of helium =32g

molar mass=atomic mass of helium

=2+2

=4u

avogadro number =$\boxed{6.022 * 10^23}$

$number \: of \: atoms = \frac{32g}{4u} \times 6.022 \times 10 { }^{23}$

$= 8 \times 6.022 \times 10 {}^{23}$

$= 48.176 \times 10 {}^{23} atoms$