Question

Calculate the number of atoms in 52 amu of helium

Answer 1

Answer:

Atomic mass of Helium is 4u = 2protons + 2 Neutrons = 1 atom. No. of atoms in 52u = 52/4 = 13 atoms.

Answer 2

Given:

52 amu of helium is present.

To Find:

The number of atoms in 52 amu of helium.

Solution:

To find the number of atoms we will follow the following steps:

1 mole of helium has 4g of helium.

1 mole in amu has a mass of 4.002602

So, the number of moles present in 52 amu of helium

$= \frac{52}{4.002602}$

$= 13 \: moles$

1 mole contains

$6.022 \times {10}^{23} atoms$

Now,

The number of atoms in 13 moles is

$13 \times 6.022 \times {10}^{23} atoms$

$= 78 \times {10}^{23} atoms$

Henceforth, the number of atoms present in 13 moles of helium is 78 × 1023 atoms

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