Calculate the number of atoms in 52 u of helium
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4 u has Avogadro no atoms i.e. 6.022*10^23
Therefore 52 u will have 52*6.022*10^23/4 atoms = 78.286*10^23 atoms
Therefore 52 u will have 52*6.022*10^23/4 atoms = 78.286*10^23 atoms
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Answer:
=7.8286 × 10^24. In 52 u of He 7.8286 × 10^24 atoms are present.
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