Calculate the number of atoms in 56g of Nitrogen
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moles in 56 gm of nitrogen=56/14=4
no of atoms = moles* Na
=4*6.023*10²³
no of atoms = moles* Na
=4*6.023*10²³
Answered by
2
given-
number of atoms in 56g of Nitrogen
solution-
1 mole of any substance contains 6.022*10∧23
mass of nitrogen= 14*2=28g
∴ no. of moles in b56 g= 56÷28 moles
=2 moles
∴no. of molecules in 2 moles of nitrogen =6.022*10∧23 *2 molecules
=12.044*10∧23 molecules
∴no.of atoms =12.044*10∧23 *2
24.088*10∧23 atoms
ans- the no of atoms in 56g of nitrogen=24.088*10∧23 atoms
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