Calculate the number of atoms in 9.2g of Na with complete solution
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we have 1 mole of Na = 23 gr = 1.602× 10*23 atoms
9.2 gr of Na = x atoms
by cross multiplication we get,
X=4× 1.602× 10*(23-1)
= 6.408× 10*22 atoms
therefore there are 6.408× 10*22atoms
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