Question

calculate the number of atoms in each of the following
a) 14g of Nitrogen (N2)?
b)14 mole atom Nitrogen (N2)?
c)14U of nitrogen (N2)?

Answer 1

Multiply 6*10^23 you will get the answer

Answer 2

Answer : The number of atoms in each,

(a) $3.011\times 10^{23}$ number of atoms

(b) $84.308\times 10^{23}$ number of atoms

(c) $0.4998$ number of atoms

Solution :

a) 14 g of Nitrogen $(N_2)$

Given : Mass of nitrogen = 14 g

Molar mass of nitrogen = 28 g/mole

First we have to calculate the moles of nitrogen.

$\text{Moles of }N_2=\frac{\text{Mass of }N_2}{\text{Molar mass of }N_2}=\frac{14g}{28g/mole}=0.5moles$

Now we have to calculate the number of atoms.

1 mole of nitrogen contains $6.022\times 10^{23}$ number of atoms

0.5 moles of nitrogen contains $0.5\times 6.022\times 10^{23}=3.011\times 10^{23}$ number of atoms

b) 14 mole of Nitrogen $(N_2)$

Given : Moles of nitrogen = 14 moles

Now we have to calculate the number of atoms.

1 mole of nitrogen contains $6.022\times 10^{23}$ number of atoms

14 moles of nitrogen contains $14\times 6.022\times 10^{23}=84.308\times 10^{23}$ number of atoms

c) 14 U of Nitrogen $(N_2)$

Given : Mass of nitrogen = $14U=14\times 1.66\times 10^{-24}=23.24\times 10^{-24}g$       $(1U=1.66\times 10^{-24}g)$

Molar mass of nitrogen = 28 g/mole

First we have to calculate the moles of nitrogen.

$\text{Moles of }N_2=\frac{\text{Mass of }N_2}{\text{Molar mass of }N_2}=\frac{23.24\times 10^{-24}g}{28g/mole}=0.83\times 10^{-24}moles$

Now we have to calculate the number of atoms.

1 mole of nitrogen contains $6.022\times 10^{23}$ number of atoms

$0.83\times 10^{-24}moles$ moles of nitrogen contains

$(0.83\times 10^{-24})\times (6.022\times 10^{23})=0.4998$ number of atoms