calculate the number of atoms of carbon and O in 72.5g isopropanol c3h7oh
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Answered by
22
C3H7OH - Molecular mass = 60
72.5 g is 72.5/60 = 1.208 moles
1 mole of C3H7OH contains 3N atoms ( N= 6.023 x 10^23) of C
1.208 moles contains 1.208 x 3N atoms = = 3.624N atoms of C
= 2.183 x 10^24 atoms of C
Similarly
no.of O atoms = 1.208N atoms = 7.276 x 10^23 atoms of O
Answered by
6
Answer:
C3H7OH - Molecular mass = 60
72.5 g is 72.5/60 = 1.208 moles
1 mole of C3H7OH contains 3N atoms ( N= 6.023 x 10^23) of C
1.208 moles contains 1.208 x 3N atoms = = 3.624N atoms of C
= 2.183 x 10^24 atoms of C
Similarly
no.of O atoms = 1.208N atoms = 7.276 x 10^23 atoms of O
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