Calculate the number of atoms of each element in 245 g of KClO3.
Answers
Answer:
: Calculate the number of atoms of each element in 245 g of KClO3.
Solution:
Molecular mass of KClO3= 39+35.5+3×16=122.5
No. of mole of KClO3= 245 g/122.5g = 2 mole
2 mole of KClO3contains
2 mole of K = 2×6.022×1023=12.044×1023 K atoms
2 mole of Cl = 2×6.022×1023=12.044×1023 Cl atoms
6 mole of O = 6×6.022×1023=36.132×1023 O atoms.
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Explanation:
Given,
Amount of KClO3 given = 245 g
To find,
The total number of atoms of each element present in the given amount of KClO3.
Solution,
We can simply solve this numerical problem by using the following process:
The atomic mass of potassium (K) = 39 grams
The atomic mass of chlorine (Cl) = 35.5 grams
The atomic mass of oxygen (O) = 16 grams
Now,
The molar mass of KClO3
= Atomic mass of potassium (K) + Atomic mass of chlorine (Cl) + {3 x Atomic mass of oxygen (O)}
= 39 grams + 35.5 grams + {3 x 16 grams}
= 39 grams + 35.5 grams + 48 grams
= 122.5 grams
As per the rules of stoichiometry;
The molar mass of a compound (M) x number of moles of the compound (n) = total mass of the compound
=> number of moles of the compound (n) = total mass of the compound ÷ Molar mass of a compound (M)
Now,
Number of moles of the compound KClO3 (n)
= total mass of the compound KClO3 ÷ Molar mass of KClO3 (M)
= 245 grams ÷ 122.5 grams
= 2 moles
=> n = 2 moles = 2 x 6.022 x 10^23 molecules
=> n = 1.2044 x 10^24 molecules
(Since 1 mole of any compound contains Avogadro's number of molecules, i.e. 6.022 x 10^23 molecules)
So,
Total number of potassium (K) atoms present in the given amount of KClO3
= 2n
= 1.2044 x 10^24 K atoms
Total number of chlorine (Cl) atoms present in the given amount of KClO3
= 2n
= 1.2044 x 10^24 Cl atoms
Total number of oxygen (O) atoms present in the given amount of KClO3
= 3 x 2n
= 3 x 1.2044 x 10^24 K atoms
= 3.6132 x 10^24 O atoms
Hence, 245 g of KClO3 contains 1.2044 x 10^24 K atoms, 1.2044 x 10^24 Cl atoms and 3.6132 x 10^24 O atoms.