calculate the number of atoms of each element in 245g of KCIO3
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Answered by
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Explanation:
no.of moles = 122.5/122.5 = 1
No.of atoms in KClO₃= 5 x 6.022 x 10²³= 30.110 x 10²³
No.of atoms in K = 6.022 x 10²³
No. of atoms in Cl = 1 x 6.022 x 10²³
No. of atoms in O₃ = 3 x 6.022 x 10²³
= 18.066 x 10²³
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no.of moles = 122.5/122.5 = 1
No.of atoms in KClO₃= 5 x 6.022 x 10²³= 30.110 x 10²³
No.of atoms in K = 6.022 x 10²³
No. of atoms in Cl = 1 x 6.022 x 10²³
No. of atoms in O₃ = 3 x 6.022 x 10²³
= 18.066 x 10²³
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Answer:
A number of an atom of an element in the compound=number of mole of the element in compound×Avagardo number.
No of moles in KClO3=122.5/122.5=1
For KClO3, Number of moles of K,Cl, and O are 1,1, and 3 respectively....
no of atoms in K is=1×6.023×10²³
no of atoms in Cl is=1×6.023×10²³
no of atoms in O is=3×6.023×10²³
Explanation:
Hope it helps you frnd......
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