Question

calculate the number of atoms of each element present in 122.5 gram of KCLO3​

Answer 1

Explanation:

= moles× avagadro no.× no.od atoms present in this molecule

for K

1×Na×1=Na

for cl

1×Na×1=Na

for O

1×Na×3=3Na

Answer 2

$\huge\red{\boxed{\bold{Solutions}}}$

• No. Of mes of KClO3$\implies$122.5/122.5 $\implies$1

(mol. Wt of KClO3 = 122.5)

$\large\underline\mathrm\blue{From \: the \: formula \: KClO3, \: we \: know \: that \: 1 }$

$\large\underline\mathrm\blue{more \: of \: KClO3 \: contains \: 1 \: mole \: of \: K \: atoms, \: 1 }$

$\large\underline\mathrm\blue{mole \: of \: Cl \: atom \: and \: 3 \: moles \: of \: O \: atoms.</p><p>}$

(1.). No. of k = 1 × 6.022 × 10^23

(2.). No. of Cl = 1 × 6.022 × 10^23

(3.). No. of O = 1 × 6.022 × 10^23

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