Question

calculate the number of atoms of each element present in 9.8 gram of sulphuric acid H2 s o4​

Answer 1

Step-by-step explanation:

Molecular weight of H2SO4 = 98

9.8 gm of H2SO4 = 9.8/98 = 0.1mole

1 mole = 6.023 x 1023 molecules

0.1 Mole = 6.023 x 1022 molecules.

One molecule of H2SO4 = 2 hydrogen atom, one sulphur atom and 4 oxygen atoms therefore

Number of hydrogen atom in 0.1 mole = 2 x 6.023 x 1022

= 12.046 x 1022

Number of sulphur atom in 0.1 mole = 1 x 6.023 x 1022

= 6.023 x 1022:-ANS

Number of oxygen atom in 0.1 mole = 4 x 6.023 x 1022

= 24.092 x 1022