Question

calculate the number of atoms of each element present in 9.8 grams of sulphuric acid , H2so4

Answer 1

Answer:

Explanation:

For H: 9.8gH2SO4(1molH2SO498gH2SO4)(2molH1molH2SO4)(6.022⋅1023atms1molH) =1.2004⋅1023 atoms / mol H.

For S: 9.8gH2SO4(1molH2SO498gH2SO4)(1molS1molH2SO4)(6.022⋅1023atms1molS) =6.022⋅1022 atoms / mol S.

For O: 9.8gH2SO4(1molH2SO498gH2SO4)(4molO1molH2SO4)(6.022⋅1023atms1molO) =2.4088⋅1023 atoms / mol O.