Calculate the number of atoms of each kind in 5.3 gram of na2co3
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heya
No. of atom = N × NA × atomicity
= 5.3 / 106 × NA × 9
= 9 / 20 × NA
No. of atom = N × NA × atomicity
= 5.3 / 106 × NA × 9
= 9 / 20 × NA
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