Question

calculate the number of atoms of each kind in 5.3grams of sodium caebonate

Answer 1

Given mass of sodium carbonate (Na2CO3) = 5.3 g
​Molar mass of  sodium carbonate = 23×2+12+16×3
                                                    = 106g/mol
Number of moles = given mass/ Molar mass
                             = 5.3/106
                           =   0.05 mol
1mole = 6.022×1023 atoms
​0.5 mole = 3.011​×1023 atoms
Hence, 5.3g of sodium carbonate contains ​3.011​×1023 atoms.

Answer 2

Answer:

same as above answer would be 3.01 X 10^22