Question

calculate the number of atoms of each kind present in 10.6 gram of Na2CO3.???​

Answer 1

Answer:

Check the attachment.

number of Na+ ions = 1.2 x 10²³

number of C-atoms = 6.02 x 10²²

number of O-atoms = 1.8 x 10²³

Answer 2

Answer:

M of sodium carbonate = 46+12+48

=106g\mol

n=10.6/106=0.1moles

1 mole sodium carbonate= 3 moles

0.1 moles sodium carbonate= 0.3×6.022× 10 to the power 23.

= 1.8 × 10 to the power 23 atoms