Calculate the number of atoms of each kind present in 10.6 g of Na2CO3 fully solved
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Answer:
Explanation:
1 mole of Na₂CO₃ = 106 g
moles in 10.6 g of Na₂CO₃ = 10.6 /106
= 0.1 mole
106 g contain atoms of oxygen = 3 x 6.022 x 10²³
10.6 contain atoms = 0.1 x 3 x 6.022 x 10²³
= 1.8 x 10²³ atoms
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