Question

Calculate the number of atoms of each kind present in 10.6 g of Na2CO3 fully solved​

Answer 1

Answer:

Explanation:

1 mole of Na₂CO₃  = 106 g 

moles in 10.6 g of Na₂CO₃ = 10.6 /106

                                          = 0.1 mole 

106 g contain  atoms of oxygen  = 3 x 6.022 x 10²³

10.6 contain atoms = 0.1 x 3 x 6.022 x 10²³

                              = 1.8 x 10²³ atoms 

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