calculate the number of atoms of each type in 3.42g of sucrose(C12H22O11)
Chemistry
Class 11
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Answer:
Number of moles of sugar=3.42/342=0.01
No of atoms of C=0.01*12*NA
NA=abagardro number=6.022*10^23
No of atoms of H=0.01*22*NA
No of atoms of O=0.01*11*NA
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Yo Flash !
Molar mass of sucrose is 342 g
If 342 g of sucrose has 6.022 × 10²³ atoms
Then,
3.42 g of sucrose would have : 3.42 × 6.022 × 10²³/342 = 6.022 × 10²¹ atoms
TGA
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