calculate the number of atoms of each type in 5.3g of Na2CO3.
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in one mole Na2CO3 = 106 g
so,
in 106 g of Na2CO3 = 6.022×10²³ electrons
in 1 g of Na2CO3 = 6.022×10²³/106 electrons
in 5.3 g of Na2CO3 = 6.022×10²³×5.3/106 = 0.3011×10²³ = 3.011×10²² electrons
so,
in 106 g of Na2CO3 = 6.022×10²³ electrons
in 1 g of Na2CO3 = 6.022×10²³/106 electrons
in 5.3 g of Na2CO3 = 6.022×10²³×5.3/106 = 0.3011×10²³ = 3.011×10²² electrons
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