Calculate the number of atoms of
hydrogen present in 5.6 g of urea,
(NH),CO. Also calculate the number
of atoms of N, C and O.
(Ans. : No. of atoms of H = 2.24 x 1023
.
N=1.124 x 1023 and C = 0.562 x 1023, 0
= 0.562 x 1023)
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Answer:
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Answered by
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Answer:
Urea→CO(NH
2
)
2
Given weight = 5.6g
∴ Moles of urea =
60
5.6
=0.0933 moles
No. of H atoms =4×0.0933×Na=2.25×10
23
atoms
No. of N atoms =2×0.0933×Na=1.123×10
23
atoms
No. of C atoms =No.ofOatoms=0.0933×Na=5.6×10
22
atoms
Explanation:
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