Calculate the number of atoms of hydrogen present in 5.6 g of urea (NH2)2 Co. Also calculate the
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Urea = NH2CONH2
M.wt = 60
5.6 g urea = 5.6/60 = 0.093 moles
1 mole of urea contains 4N atoms of H
0.093 moles contains 0.093 x 4N atoms of H
= 2.24 x 10^23 atoms of H
No of atoms of Nitrogen = half of the number of atoms of H
= 1.12 x 10^23 atoms of N
No of atoms of C or O = half of the number of atoms of N
= 0.56 x 10^23 atoms of C or O
= 5.6 x 10^22 atoms of C or O
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