Question

Calculate the number of atoms of hydrogen present in 5.6
g of urea (NH2)2CO​

Answer 1

Explanation:

2.247 ×1023 atoms of hydrogen .

Answer 2

Explanation:

Molar mass of urea = 60g/mol

Number of moles of urea = n= w/M

= 5.6/60 =0.09333mol

Now,

∴ 1 mol urea contains 4 gram atoms of hydrogen(H)

∴ 0.09333mol urea contains=4×0.09333=0.3733 gram atom of H.

Now,

1gm atom of H contains =6.022×10^23 atoms of H.

0.3733gram atom of hydrogen contain

= 6.022×10^23×0.3733

=2.248×10 ^23