Question

Calculate the number of atoms of hydrogen present in 5.6 g of urea, (NH2)2CO. Also calculate the number of atoms of N, C and O​

Answer 1

Explanation:

Mass of urea = 5.6 g

To find: The number of atoms of hydrogen, nitrogen, carbon, and oxygen

Calculation: Molecular formula of urea:

(NH₂)2CO Molar mass of urea = 60 g mol-1

Number of moles =

Mass of a substance

Molar mass of a substance

5.6g

0.0933 mol

60g mol

Moles of urea = 0.0933 mol

Number of atoms = Number of moles x Avogadro's constant

Now, 1 molecule of urea has total of 8 atoms, out of which 4 atoms are of H, 2 atoms are of N, 1 of C, and 1 of O.

Number of H atoms in 5.6 g of urea = (4 x

0.0933) mol x 6.022 x 1023 atoms/mol

= 2.247 x 1023 atoms of hydrogen

2.247 x 1023 atoms of hydrogen

Number of N atoms in 5.6 g of urea = (2x

0.0933) mol x 6.022 × 1023 atoms/mol

= 1.124 x 1023 atoms of nitrogen

Number of C atoms in 5.6 g of urea = (1 x

0.0933) mol x 6.022 x 1023 atoms/mol

= 0.562 × 1023 atoms of carbon

Number of O atoms in 5.6 g of urea = (1 x

0.0933) mol x 6.022 x 1023 atoms/mol

= 0.562 × 1023 atoms of oxygen

5.6 g of urea contains 2.247 x 1023 atoms of H, 1.124 x 1023 atoms of N, 0.562 × 1023 atoms of C, and 0.562 x 1023 atoms of 0.

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