Question

calculate the number of atoms of hydrogen present in 5.6g of urea, (NH2)2CO also calculate the number of atoms of N, C and O​

Answer 1

Answer:

For H = 2.248 X 10^23

For N =1.08 x 10^23

For C = 5.4 x 10^22

For O = 5.4 x 10^22

Explanation:

Molar mass of urea = 60g

thus, 1 g of urea has 0.01667 moles.

Then, 5.6 g of urea has 0.0933 moles     -   total molecules = 5.620 x 10^22

Then, the number of atoms of hydrogen are : 5.620 x 4 x 10^22 = 2.248 x 10^23

    Similarly calculate for N, C, O