calculate the number of atoms of hygrogen present in5.6 of uera also calculate the number of atom of N,C AND O
Answers
Explanation:
Urea(NH2CONH2) has molecular wt.60gm
No.of entity=No.of moles*Avagdro's no.*entity count is the formula we are using here
No.of atoms for hydrogen =5.6/60*6.02*10^23*4(as 4 atoms of hydrogen are present in urea)
=2.24*10^23
Similarly use 2 atoms of Nitrogen and 1 atom of Oxygen and Carbon each in place of entity count to get your answer
I hope it'll help you;)
Answer:
once you get the no of molecules in a given sample of substance..... Find the no of atoms per molecule of a particular element(here H atom) and then multiply it with the total no of molecules in the given sample.. u can do the same for O,C and N
i. e multiply 5.621*10^22 with 1 for calculating no of atoms of oxygen.... 5.621*10^22 with 2 for calculating no of atoms of N....
hope it helps
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