calculate the number of atoms of oxygen present in 120 gram of nitric acid
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1 mole nitric acid has 6.022×10^23 oxygen atoms i,e. 63 gm has 6.022 ×10^23 oxygen atoms.
By unitary method,
63-----》6.022×10^23 atoms
1-------》6.022×10^23/63 atoms
120------》6.022×10^23×120/63
=6.022 ×10^23×1.904
=11.47×10^23 atoms
By unitary method,
63-----》6.022×10^23 atoms
1-------》6.022×10^23/63 atoms
120------》6.022×10^23×120/63
=6.022 ×10^23×1.904
=11.47×10^23 atoms
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