Question

Calculate the number of atoms of oxygen present in 132g of co2. what would be the weight of co having the same number of oxygen atom.

Answer 1

number of oxygen atoms = number of moles × Avogadro's constant

here, given,
weight of oxygen = 132 g
molecular weight of CO2= 44g/mol

number of moles = given wt/mol.wt
= 132g/44g/mol = 3

we know,
in 1 mole of CO2 , 2 moles of oxygen present .
so , in 3 moles of CO2, 6 moles of oxygen present .

now, no of oxygen atoms = 6 × 6.023 × 10²³ = 36.138 × 10²³ = 3.6138 × 10²⁴


again,
no of oxygen atoms in CO2 = no of oxygen atoms in CO

3.6138 × 10²⁴ = no of moles of O in CO × Avogadro's constant

6 = no of moles of O in CO

we know,
no of moles of CO = no of mole of O in CO

so,
no of moles of CO = 6
wt of CO/mol.wt = 6

wt of CO = 6 × 28 = 168 g

Answer 2

Answer:

168g

Explanation: