Question

calculate the number of atoms of oxygen present in 88g of CO2 what would be the weight of CO having same number of oxygen atoms? ​

Answer 1

Answer:

Explanation:Molecular weight of CO2 =44 and it has 32g O2 and one molecule of O2 has 2 atoms.

44gCO2 has 2N atoms of O

88g CO2 has 2N atoms =2×6.023×1023×8844

⇒24.092×1023atoms of O2

CO=28

N atoms of O present in 28g CO

24.092×1023 atoms of O=28×24.092×10236.023×1023

⇒112g CO

Hence (b) is the correct option.