calculate the number of atoms of oxygen present in 88gm of co2? what would be the weight of co having the same number of oxygen atoms
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Answer:
88gCO
2
= 2 moles of CO
2
. One molecule consists of 2 oxygen atoms.
No. of oxygen atoms =2×2×6.02×10^
23
=24.08×10^23
CO molecule has one oxygen atom.
Mass of CO containing 24.08×10
23
oxygen atoms
=
6.02×10 ^23
28
×24.08×10
23
=112g
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