calculate the number of atoms of the Constituents elements in 53g of Na2CO3. (atomic masses Na = 23 ,C= 12, O =16)
Answers
Answered by
0
Answer:
Huddleston and I know you want to tell the story is a very good idea to do hand stand easily for kids morning
Answered by
2
Answer:
number of moles = mass÷molar mass
= 53÷106
=0.5 moles.
1 mole has 6.022× 10^23 atoms.
0.5 moles has 6.022×10^23÷2 atoms = 3.011×10^23 atoms...
Similar questions