Question

calculate The number of atoms present 0.5 moles of nitrogen (N) . ​

Answer 1

Answer:

=6.022×1023×0.5=3.01×1023 atoms.

Explanation:

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Answer 2

Answer:

3.01 ×1023 Atoms

Explanation:

1Mole=6.022×10 power 23

Given Here

Element=Nitrogen{N}

No.of Moles Present in Nitrogen=0.5 Moles

No.of Atoms present in 0.5 Moles=?

=6.022×10 power 23 ×0.5Moles

=3.01×1023 Atoms

∆So,no.of Atome present in 0.5 Moles of Nitrogen{N} are "3.01×1023 Atoms.....

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