Question

calculate the number of atoms present in 1 drop of water having mass 1.8 g​

Answer 1

●Hey dear

Explanation:

1 mole of water = gram atomic mass of water

•°•H2O = 2×1+16.

. = 18grams

we know that 1 mole of H2O contains 6.022×10^23

now,

18g of water contains = 6.022×10^23

so,

1.8 g of water Contains 6.022×10^23 /56 × 1.8

●HOPE ITS HELPFULL