Question

calculate the number of atoms present in 11.2 litres of co2
gas at STP

Answer 1

we Know that:-

Volume of 1 mole of any gas =22.4 Litres.

Given volume of carbondioxide= 11.2 Litres.

$\boxed{\bold{\red{\sf{\Large{Number\:of\:moles=\dfrac{given\:volume}{22.4}}}}}}$

Thus,

Given moles of carbondioxide will be as follows :-

$moles=\dfrac{11.2}{22.4}\\ \\ \\moles=\dfrac{1}{2}\\ \\ \\moles=0.5 moles$

now,

we know that :-

Number of molecules in 1 mole of any compound will be :-

$\boxed{\bold{\red{\sf{Molecules=Number\:of\:moles*N_A}}}}$

where:-

$N_A=Avogadro's\:Number$

$\rule{200}{2}$

Number of molecules of CO2 given will be :-

$=0.5*N_A\:Molecules$

$\rule{200}{2}$

we know that :-

1 molecule of CO2 has total 3 atoms.

Hence,

Total atoms present in 11.2 Litres of CO2 at STP will be as follows:-

$=3*0.5*N_A\:Atoms\\ \\ \\=1.5N_A\:Atoms$

where:-

$N_A=6.022*10^{23}$

Answer 2

Answer:22.4 l= 6.022×10^23

So for 11.2 l = 6.022×10^23/2

= 3.022×10^23

Explanation: