Question

Calculate the number of atoms present in 2 gram of helium

Answer 1

Answer:

2g of helium contains 3 × 10²³ Atoms.

Explanation:

1 mole ( 6 × 10²³ atoms) of helium has 4 gram approximately.

So when there is 2 gram of helium it must contain half the atoms in 1 mole.

i.e 2g of helium = (6 × 10²³) ÷ 2

= 3 × 10²³ atoms.

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