Question

Calculate the number of atoms present in 24 g of helium

Answer 1

Answer:

Number of atoms = 72.264 * 10²³

Explanation:

We know that,

Number of moles = $\dfrac{Given \ mass}{Molar \ mass}$

and

Number of moles = $\dfrac{Number \ of \ particles}{Avogadro \ number}$

Therefore,

$\dfrac{Given \ mass}{Molar \ mass} = \dfrac{Number \ of \ particles}{Avogadro \ number}$

In the given question,

Given mass = 24g

Molar mass of He = 2g

Avogadro number = 6.022 * 10²³

Number of particles = ?

Substituting these values in we get,

$\dfrac{24}{2} = \dfrac{Number \ of \ particles}{6.022 * 10^{23}}$

$Number \ of \ particles = 12 * (6.022 * 10^{23})$

$Number \ of \ particles = 72.264 * 10^{23}$

Answer 2

Answer:

Real no  of atoms in 2g=6.02*10^23

no of atoms in 24g=2/24*6.02*10^23

=3.01*10^24

Explanation: