Question

Calculate the number of atoms present in 24 g of helium. (He=4u)

Answer 1

Answer:

refer this..............

Answer 2

$\huge{\underline{\sf{\blue{Solution:\rightarrow}}}}$

$\sf{ Atomic\ mass\ of \ He = 4u}$

$\sf{ Mass\ of\ 1\ mole\ of\ He= 4g}$

$\sf{1mole \ He= 6.022\times 10^{23} }$

$\sf{4u\ of\ He= \dfrac{6.022\times10^{23}}{4}}$

$\sf{ 24 g \ of\ He= \dfrac{6.022\times 10^{23}}{4} \times 24 }$

               $\sf{= 36.152\times 10^{23} Atoms}$