Question

calculate the number of atoms present in 24 grams of helium

Answer 1

Answer:

1 mole of He contains 6.023×10^23 atoms.

1 mole of He = 4 gm of He.

So, 20 gm of He contains — (20÷4)×6.023×10^23 atoms = 3.011×10^24 He atoms.

Answer 2

Explanation:

WE know , 1mole of helium atom = atomic weight = 4  

so, i mole of helium atom = 6.023 × 10²³ atoms

for  for, 20 g of He = 20÷ 4 × 6.022× 10 ²³

                            = 3.011 × 10^ 24 He atoms

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