Question

Calculate the number of atoms present in 24g of Helium.​

Answer 1

Answer:

1 mole of He contains 6.023×10^23 atoms.

1 mole of He = 4 gm of He.

So, 20 gm of He contains — (20÷4)×6.023×10^23 atoms = 3.011×10^24 He atoms.

Explanation:

Answer 2

1 mole of He contains 6.023×10^23 atoms.

1 mole of He = 4 gm of He.

So, 20 gm of He contains — (20÷4)×6.023×10^23 atoms = 3.011×10^24 He atoms.