Question

Calculate the number of atoms present in 4gram of hydrogen gas?

Answer 1

Answer:

N(N2)=m/M=1.4/14=0.1mole

N(atoms)=n*NA(avogadros number)=0.1*6*10^23=6*10^22 atoms

Answer 2

Answer:

Since 2 grams of H₂ is 1 mole and 1 mole consists of 6.022 × 10²³ atoms

Therefore 4 grams of H₂ is 4/2= 2 moles,

hence no. of atoms = 6.022× 10²³ ×2

                                 =12.044×10²³

                                = 1.2044 × 10²⁴