Question

Calculate the number of atoms present in
52 moles of He
52 amu He
52g He

Answer 1

Hii There!!!

1)  1 mole of He contains 6.023x10^23
So, 52 moles of He contains 52 x 6.023 x10^23atoms

2) Atomic mass of Helium is 4u
= 2protons + 2 Neutrons = 1 atom 

So, The number of atoms in 52u = 52/4 = 13 atoms.


3) 4g of He has 1 mole 

=) 1g of He has 1/4 mole 

So, 52g of He has 1/4 x 52 = 13 moles 

Since, 1 mole=6.022x10^23atoms 

So, 13 moles 13x6.023x10^23 atoms.



Hope it helps☺️

Answer 2

The number of atoms present in different quantities of Helium are as follows:

Given:

• 52 moles of Helium.
• 52 amu of Helium.
• 52g of Helium.

To find:

• The number of atoms in different quantities of Helium.

Formula used:

Number of moles = Given Mass/Molecular Mass

Number of moles = No. of atoms/Avogrado Number

No. Of atoms = No. of moles x Avogadro number.

Explanation:

1. 52 moles of Helium:

No. of atoms = 52 x 6.022 x $10^{23}$ = 3.13 x $10^{25}$

2. 52 amu of Helium:

No. of atoms = 52/4 = 13

3. 52g of He:

No. of moles = 52/4 = 13

No. of atoms = 13 x 6.022 x $10^{23}$ = 7.83 x $10^{24}$

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