Question

Calculate the number of atoms present in 56 ml of CO2

Answer 1

Answer:

15*10²¹

Explanation:

No of moles = volume(inml) /22.4*1000

56/22400=0.0025

No. Of moles = no. Of atoms / avagadros number

0.0025= no. Of atoms /6*10²³

0.0025*6*10²³= 15*10²³

Answer 2

Answer:

66.242 × 10 raised to the power 21

Explanation:

Molecular mass of gas at STP=22.4 litre

1 litre=1000 ml

Therefore,22.4 litre=22.4×1000=22400ml

Molecular mass of CO2 at STP

=(44 × 22400)gm

No of moles=56 ÷ (44 ×22400)

=0.11 moles

No of molecules=No of moles× avagadro no.

=0.11×6.022×10 raised to the power 23

=66.242 ×10 raised to the power 21

Ans:The number of atoms/molecules present in 56 ml of CO2 is 66.242 × 10 raised to the power 21

Hopefully this is the answer.