Question

Calculate the number of atoms present in 56g of carbon dioxide

Answer 1

Answer:

7.23 X 10²⁵ atoms

Explanation:

Given= m (given mass)= 56g

            M (molar mass)= sum of the atomic masses of carbon atom and oxygen atom X 2 expressed in grams.

C= 12u

O= 16u; O₂ = 16 X 2 = 32u

CO₂ = 32 + 12 is grams

M = 44g

N₀ (Avogadro's number) = 6.022 X 10²³

n (number of moles) = ?

N (number of particles) = ?

Formula: We know that N = n X N₀ and

n= m/M

On substituting the formula of n in the 1st equation, we get

N = m/M X N₀

Procedure: On substituting the values in this formula, we get

N = 56/44 X 6.022 X 10²³

N = 722.64 X 10²³

N = 7.2264 X 10²⁵

N = 7.23 X 10²⁵ atoms [approx.]