calculate the number of atoms present in 6.4 g of sulphur.
Answers
Answered by
36
number of mole = weight/ atomic weight
= 6.4/32
= 0.2 mole
1 mole = 6.023*10^23 atom
hence
0.2 mole - 0.2*6.023*10^23 atom
0.2 mole = 1.2046*19^23 atom
= 6.4/32
= 0.2 mole
1 mole = 6.023*10^23 atom
hence
0.2 mole - 0.2*6.023*10^23 atom
0.2 mole = 1.2046*19^23 atom
Answered by
10
number of moles=weight/atomic weight
=6.4/32
=0.2
=6.4/32
=0.2
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