Question

calculate the number of atoms present in 8 grams of iron metal.given atomic mass of iron is 56

Answer 1

Explanation:

n=wt/gmw

n=8/56

n=1/7

no of atoms= n×atomicity×avagadro's no

1/7×1×6.022×10^23

therefore ans is 0.86×10^23

Answer 2

$0.860\times 10^{23}$ atoms of iron are present in 8 grams of iron metal.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{8g}{56g/mol}=0.14moles$

1 mole of iron $(Fe)$ contains = $6.023\times 10^{23}$ atoms of iron

0.14 mole of iron $(Fe)$ contain= $\frac{6.023\times 10^{23}}{1}\times 0.14=0.860\times 10^{23}$ atoms of iron.

Learn more about moles

https://brainly.in/question/12937992

https://brainly.com/question/11880336

#learnwithbrainly